.2x^2-11.6x=0

Solution for .2x^2-11.6x=0 equation:

.2x^2-11.6x=0

a = .2; b = -11.6; c = 0;
Δ = b2-4ac
Δ = -11.62-4·.2·0
Δ = 134.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.6)-\sqrt{134.56}}{2*.2}=\frac{11.6-\sqrt{134.56}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.6)+\sqrt{134.56}}{2*.2}=\frac{11.6+\sqrt{134.56}}{0.4}
$